Pbo Carbon
How do you do this chemistry problem?
Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon.
PbO(s) + C(s) Pb(l) + CO(g)
Calculate the expected yield of lead if 86.0 kg of lead oxide is heated with 33.0 kg of carbon.
Step 1: make sure your equation is balanced (which it is)
Step 2: determine the limiting reactant. For this you can pick either of the molecules... i'm going to pick the lead oxide. First you have to find how many moles of the PbO would react with C.
86000g PbO/223.2 (it's molecular weight) = 385mol
looking at the coefficients you can tell 1 mol of PbO reacts with 1 mol of C. This means you would need 385 mol of C to react with that much PbO. This amount in grams of C is 385mol x 12.06g (it's molecular weight)= 4640g= 4.64kg You have way more than that (you have excess C) so that means that PbO is the limiting reactant
Step 3: once you've found the limiting reactant use that to find out how much product the reaction would yeild:
From the last step we already know that we have 385 mol of PbO. Looking at the coefficients of the balanced equation for every one mole of PbO you have one mole of Pb. That means you will have 385 mols of Pb produced. assuming they want the answer in kg you need to convert mols to kg by multiplying by it's molecular weight
385mol x 207.2g= 79772= 79.8kg
you would have 79.8kg of Pb produced.
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